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Post by account_disabled on Dec 12, 2017 10:30:50 GMT
Hi, I am trying to understand transistor mechanics. In a common emitter circuit ( where a resistor is connected to the collector ): When the base voltage is HIGH, CE resistance is LOW (closed switch) and so C is connected to GND (LOW). When the base voltage is LOW, CE resistance is HIGH (open switch) and so the pull up resistor pulls C to Vcc (HIGH). In the active mode of the transistor, this results in an inverse phase between the input signal and the output signal voltages. I think the currents Ib and Ic would fluctuate in phase with the fluctuations of the voltages in their respective circuit loops. This would mean that when Ib is high, Ic will be low. If this is correct, then the relationship Ic=hfe*Ib does not seam to give a snapshot info of what is happening. That is to say, If I freeze the circuit at any particular time and take readings of Ic and Ib, won't I find that when Ib is up then Ic is down? Any idea? Please help. Thanks! I didn't find the right solution from the Internet. References forum.allaboutcircuits.com/threads/common-emitter-npn-ib-and-ic.141079/Technology Explainer Video
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